Which one of the orders is correctly matched | vedclass

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(B) $1$. For option $A$: The boiling point order of group $16$ hydrides is $H_2S < H_2Se < H_2Te < H_2O$. $H_2O$ has the highest boiling point due to

Vedclass · Accepted Answer

$N_2O < NO < N_2O_3 < N_2O_4 < N_2O_5$ (Acidic nature)

Vedclass · Answer

(B) $1$. For option $A$: The boiling point order of group $16$ hydrides is $H_2S $2$. For option $B$: The acidic nature of nitrogen oxides increases with the oxidation state of nitrogen. The oxidation states are: $N_2O (+1), NO (+2), N_2O_3 (+3), N_2O_4 (+4), N_2O_5 (+5)$. The order $N_2O $3$. For option $C$: The acidic strength of hydrohalic acids increases down the group as bond dissociation energy decreases: $HF $4$. For option $D$: The bond angle decreases down the group as the electronegativity of the central atom decreases: $H_2O (104.5^{\circ}) > H_2S (92^{\circ}) > H_2Se (91^{\circ}) > H_2Te (90^{\circ})$. Thus,$D$ is incorrect.

Which one of the orders is correctly matched with the property mentioned against it?

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