Which one of the following statements is not | vedclass

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(B) Phosphine $(PH_3)$ reacts with $CuSO_4$ solution to form a black precipitate of cupric phosphide $(Cu_3P_2)$,not $CuHPO_4$.$3 CuSO_4 + 2 PH_3 \lon

Vedclass · Accepted Answer

It reacts with $CuSO_4$ solution to form $CuHPO_4$

Vedclass · Answer

(B) Phosphine $(PH_3)$ reacts with $CuSO_4$ solution to form a black precipitate of cupric phosphide $(Cu_3P_2)$,not $CuHPO_4$.$3 CuSO_4 + 2 PH_3 \longrightarrow Cu_3P_2 + 3 H_2SO_4$$PH_3$ is a very weak base.It is prepared by the reaction of calcium phosphide with $HCl$:$Ca_3P_2 + 6 HCl \longrightarrow 2 PH_3 + 3 CaCl_2$$PH_3$ is used in smoke screens (Holm's signals).Therefore,statement $(B)$ is incorrect.

Which one of the following statements is not correct regarding phosphine?

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