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(A) The law of reciprocal proportions states that if two different elements combine separately with a fixed mass of a third element,the ratio of the m

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$P_2O_3, PH_3$ and $H_2O$

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(A) The law of reciprocal proportions states that if two different elements combine separately with a fixed mass of a third element,the ratio of the masses in which they do so is either the same or a simple multiple of the ratio of the masses in which they combine with each other.In the set $P_2O_3, PH_3$ and $H_2O$:$1$. $P$ combines with $H$ to form $PH_3$ ($31 \ g$ of $P$ with $3 \ g$ of $H$).$2$. $P$ combines with $O$ to form $P_2O_3$ ($62 \ g$ of $P$ with $48 \ g$ of $O$).$3$. For a fixed mass of $P$ $(62 \ g)$,the mass of $H$ is $6 \ g$ and the mass of $O$ is $48 \ g$. The ratio is $6:48 = 1:8$.$4$. In $H_2O$,$H$ and $O$ combine in the ratio $2:16 = 1:8$.Since the ratios are the same,this set illustrates the law.

Which one of the following sets of compounds correctly illustrates the law of reciprocal proportions?

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