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(A) From the ideal gas equation,we have $p V=n R T$.For one mole of an ideal gas,$n=1$,so the equation becomes $p V=R T$.Here,$R$ is the universal gas

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(A) From the ideal gas equation,we have $p V=n R T$.For one mole of an ideal gas,$n=1$,so the equation becomes $p V=R T$.Here,$R$ is the universal gas constant,which is approximately $8.314 \ J \cdot mol^{-1} \cdot K^{-1}$.The equation $p V=R T$ represents a straight line passing through the origin with a slope equal to $R$.The dotted line represents $p V=T$,which is a straight line passing through the origin with a slope of $1$.Since $R \approx 8.314 > 1$,the slope of the line $p V=R T$ must be greater than the slope of the line $p V=T$.Therefore,the graph where the solid line (representing $p V=R T$) has a steeper slope than the dotted line (representing $p V=T$) is the correct representation.

Which one of the following schematic graphs best represents the variation of $p V$ (in Joules) versus $T$ (in Kelvin) of one mole of an ideal gas? (The dotted line represents $p V=T$)

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