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(A) $CH_{3}NC + 4[H] \xrightarrow{LiAlH_{4}} CH_{3}NHCH_{3}$$CH_{3}NC$ (Methyl isocyanide) on reduction with lithium aluminium hydride $(LiAlH_{4})$ y

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Methyl isocyanide

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(A) $CH_{3}NC + 4[H] \xrightarrow{LiAlH_{4}} CH_{3}NHCH_{3}$$CH_{3}NC$ (Methyl isocyanide) on reduction with lithium aluminium hydride $(LiAlH_{4})$ yields $CH_{3}NHCH_{3}$ (Dimethylamine),which is a secondary $(2^{\circ})$ amine.In contrast,reduction of alkyl cyanides $(RCN)$ with $LiAlH_{4}$ yields primary $(1^{\circ})$ amines $(RCH_{2}NH_{2})$.Reduction of acetamide $(CH_{3}CONH_{2})$ yields ethylamine $(CH_{3}CH_{2}NH_{2})$,a primary amine.Reduction of nitroethane $(CH_{3}CH_{2}NO_{2})$ yields ethylamine $(CH_{3}CH_{2}NH_{2})$,a primary amine.

Which one of the following on reduction with lithium aluminium hydride yields a secondary amine?

Similar Questions

The hydrolysis of alkyl isocyanides $(R-CH_2-NC)$ gives:

What is the correct order of basicity for the following compounds?
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$2$. $CH_3CH_2NH_2$ (Ethylamine)
$3$. $(CH_3)_2NH$ (Dimethylamine)
$4$. $CH_3CONH_2$ (Acetamide)

Amines are basic in nature because:

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Which of the following is converted into an alcohol on treatment with $HNO_2$?

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