Which one of the following is the correct set | vedclass

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(B) The rules for quantum numbers are as follows:$1$. Principal quantum number $n$ can be any positive integer $(1, 2, 3, ...)$.$2$. Azimuthal quantum

Vedclass · Accepted Answer

$(4, 3, -2, -\frac{1}{2})$

Vedclass · Answer

(B) The rules for quantum numbers are as follows:$1$. Principal quantum number $n$ can be any positive integer $(1, 2, 3, ...)$.$2$. Azimuthal quantum number $\ell$ ranges from $0$ to $n-1$.$3$. Magnetic quantum number $m$ ranges from $-\ell$ to $+\ell$.$4$. Spin quantum number $s$ can be $+\frac{1}{2}$ or $-\frac{1}{2}$.Evaluating the options:$A$: $(3, 0, -1, +\frac{1}{2})$ is incorrect because $m$ cannot be $-1$ when $\ell=0$.$B$: $(4, 3, -2, -\frac{1}{2})$ is correct because for $n=4$,$\ell=3$ is allowed,and for $\ell=3$,$m=-2$ is allowed.$C$: $(3, 1, -2, -\frac{1}{2})$ is incorrect because $m$ cannot be $-2$ when $\ell=1$.$D$: $(4, 2, -3, +\frac{1}{2})$ is incorrect because $m$ cannot be $-3$ when $\ell=2$.

List-$I$ (Quantum number)	List-$II$ (Orbital)
$a. n=2, \ell=1$	$i. 2s$
$b. n=3, \ell=2$	$ii. 3s$
$c. n=3, \ell=0$	$iii. 2p$
$d. n=2, \ell=0$	$iv. 3d$

Which one of the following is the correct set of four quantum numbers $(n, l, m, s)$?

Similar Questions

On the basis of quantum numbers,justify that the sixth period of the periodic table should have $32$ elements.

Match List-$I$ with List-$II$ :
List-$I$ (Quantum number) List-$II$ (Orbital)
$a. n=2, \ell=1$ $i. 2s$
$b. n=3, \ell=2$ $ii. 3s$
$c. n=3, \ell=0$ $iii. 2p$
$d. n=2, \ell=0$ $iv. 3d$

Choose the correct answer from the options given below :

The principal quantum number of an atom is related to the:

The orbital angular momentum of an electron in a $d-$orbital is $:-$

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