Which one of the following is the correct decreasing order of boiling point?
- A$H_2Te > H_2O > H_2Se > H_2S$
- B$H_2O > H_2S > H_2Se > H_2Te$
- C$H_2Te > H_2Se > H_2S > H_2O$
- D$H_2O > H_2Te > H_2Se > H_2S$
Explore More
Similar Questions
Match List-$I$ with List-$II$ :
List-$I$ (Oxoacids of Sulphur) List-$II$ (Bonds) $A$. Peroxodisulphuric acid $I$. Two $S-OH$,Four $S=O$,One $S-O-S$ $B$. Sulphuric acid $II$. Two $S-OH$,One $S=O$ $C$. Pyrosulphuric acid $III$. Two $S-OH$,Four $S=O$,One $S-O-O-S$ $D$. Sulphurous acid $IV$. Two $S-OH$,Two $S=O$
Choose the correct answer from the options given below.
| List-$I$ (Oxoacids of Sulphur) | List-$II$ (Bonds) |
| $A$. Peroxodisulphuric acid | $I$. Two $S-OH$,Four $S=O$,One $S-O-S$ |
| $B$. Sulphuric acid | $II$. Two $S-OH$,One $S=O$ |
| $C$. Pyrosulphuric acid | $III$. Two $S-OH$,Four $S=O$,One $S-O-O-S$ |
| $D$. Sulphurous acid | $IV$. Two $S-OH$,Two $S=O$ |
Choose the correct answer from the options given below.
MediumNEET 2023
View SolutionWhich one among the following has the $S-O-S$ bonding?
$H_2S$ is less acidic than $H_2Te$. Why?
Easy
View SolutionIn the following,the oxoacid with a peroxy bond is
Acidity of diprotic acids in aqueous solutions increases in the order:
DifficultNEET 2014
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo