Which one of the following has a square plana | vedclass

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(C) The correct answer is $[PtCl_4]^{2-}$.$Pt$ is a $5d$ series element. For $5d$ series elements,the crystal field splitting energy is high,so even w

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$[PtCl_4]^{2-}$

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(C) The correct answer is $[PtCl_4]^{2-}$.$Pt$ is a $5d$ series element. For $5d$ series elements,the crystal field splitting energy is high,so even weak field ligands like $Cl^-$ can cause pairing of electrons.$Pt^{2+}$ has a $5d^8$ configuration. Due to the pairing of electrons,it undergoes $dsp^2$ hybridisation,resulting in a square planar geometry.In contrast,$[FeCl_4]^{2-}$,$[NiCl_4]^{2-}$,and $[CoCl_4]^{2-}$ involve $3d$ series metals where $Cl^-$ acts as a weak field ligand and cannot cause pairing. Thus,they undergo $sp^3$ hybridisation and exhibit tetrahedral geometry.

Which one of the following has a square planar geometry?

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