Which one of the following group-15 hydrides | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reducing character of group-$15$ hydrides depends on the bond dissociation enthalpy of the $E-H$ bond. As we move down the group from $N$ to $

Vedclass · Accepted Answer

$BiH_3$

Vedclass · Answer

(C) The reducing character of group-$15$ hydrides depends on the bond dissociation enthalpy of the $E-H$ bond. As we move down the group from $N$ to $Bi$,the atomic size increases,which leads to a decrease in the bond dissociation enthalpy of the $E-H$ bond. Consequently,the stability of the hydrides decreases and the reducing character increases. Therefore,$BiH_3$ has the lowest bond dissociation enthalpy and is the strongest reducing agent among the group-$15$ hydrides.

Which one of the following group-$15$ hydrides is the strongest reducing agent?

Similar Questions

Which of the following reacts with $Fe(II)$ ions to form a brown complex?

The most stable hydride is

The reaction of zinc with dilute and concentrated nitric acid,respectively,produces:

Explain the nature of oxide compounds of group-$15$ elements.

The $+1$ oxidation state in group $13$ and $+2$ oxidation state in group $14$ become more stable with increasing atomic number. Explain.

Vedclass Test Series

Exam Paper Generator

Online Exam Module