Which one of the following compounds is not a | vedclass

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(C) To determine if a compound is aromatic,it must satisfy $H$ückel's rule: it must be cyclic,planar,fully conjugated,and have $(4n + 2) \pi$ electron

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Cyclooctatetraene

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(C) To determine if a compound is aromatic,it must satisfy $H$ückel's rule: it must be cyclic,planar,fully conjugated,and have $(4n + 2) \pi$ electrons.$A$. Cycloheptatrienyl anion: It has $8 \pi$ electrons (anti-aromatic) or is non-planar,but in many contexts,it is considered non-aromatic due to lack of planarity or anti-aromaticity.$B$. Cyclopentadienyl anion: It has $6 \pi$ electrons $(n=1)$,is cyclic,planar,and fully conjugated. It is aromatic.$C$. Cyclooctatetraene: It has $8 \pi$ electrons ($4n$ system). It is non-planar (tub-shaped) to avoid anti-aromaticity,making it non-aromatic.$D$. Phenol: It is a benzene derivative,which is aromatic.Comparing the options,Cyclooctatetraene is the most classic example of a non-aromatic compound due to its non-planar structure.

Which one of the following compounds is not aromatic?

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