Which one of the following compounds is a per | vedclass

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Question

(B) In a peroxide,the oxidation number of $O$ is $-1$,and they contain a peroxide linkage $(-O-O-)$. They react with dilute acids to produce $H_2O_2$.

Vedclass · Accepted Answer

$BaO_2$

Vedclass · Answer

(B) In a peroxide,the oxidation number of $O$ is $-1$,and they contain a peroxide linkage $(-O-O-)$. They react with dilute acids to produce $H_2O_2$.For $KO_2$: Let the oxidation state of $O$ be $x$. Then $1 + 2x = 0$,so $x = -\frac{1}{2}$. This is a superoxide.For $BaO_2$: Let the oxidation state of $O$ be $x$. Then $2 + 2x = 0$,so $x = -1$. This is a peroxide.For $MnO_2$ and $NO_2$: These are dioxides where the oxidation state of $O$ is $-2$. Therefore,they are not peroxides.Thus,$BaO_2$ is the correct answer.

Which one of the following compounds is a peroxide?

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