Which one of the following compounds cannot b | vedclass

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(A) The Wurtz reaction involves the coupling of two alkyl halide molecules in the presence of sodium metal to form a symmetrical alkane with an even n

Vedclass · Accepted Answer

$CH_4$

Vedclass · Answer

(A) The Wurtz reaction involves the coupling of two alkyl halide molecules in the presence of sodium metal to form a symmetrical alkane with an even number of carbon atoms. $2R-X + 2Na \rightarrow R-R + 2NaX$. Since the reaction requires at least two alkyl groups to join,the smallest alkane that can be formed is ethane $(C_2H_6)$. Therefore,methane $(CH_4)$ cannot be prepared by the Wurtz reaction because it contains only one carbon atom.

Which one of the following compounds cannot be prepared by Wurtz reaction?

Similar Questions

Explain: Alkyl group.

Which is the correct option for the following reaction?
$ 2 CH_3 CH_2 Br \xrightarrow{2 Na / \text{Dry ether}} ? $

Consider the following:
Statement-$I$ : Kolbe's electrolysis of sodium propionate gives $n$-hexane as product.
Statement-$II$ : In Kolbe's process,$CO_2$ is liberated at the anode and $H_2$ is liberated at the cathode.
The correct answer is:

$CH_3-CH_2-CH_2-CH_3 \xrightarrow[\Delta]{AlCl_3} CH_3-CH(CH_3)-CH_3$
The above reaction is an example of:

The addition of tetraethyl lead to petrol:

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