Which one of the following cannot be prepared | vedclass

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Question

(A) The Wurtz reaction involves the coupling of two alkyl halide molecules to form a symmetric alkane with an even number of carbon atoms. $CH_4$ (met

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$CH_4$

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(A) The Wurtz reaction involves the coupling of two alkyl halide molecules to form a symmetric alkane with an even number of carbon atoms. $CH_4$ (methane) contains only one carbon atom. Since the Wurtz reaction requires at least two alkyl groups to combine,it is impossible to form a single-carbon alkane like methane. Therefore,$CH_4$ cannot be prepared by this method.

Which one of the following cannot be prepared by Wurtz reaction?

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