Which one of the following alkali metals is t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The reducing power of a metal is determined by its standard electrode potential $(E^{\circ})$. $A$ more negative $E^{\circ}$ value indicates a str

Vedclass · Accepted Answer

$Na$

Vedclass · Answer

(D) The reducing power of a metal is determined by its standard electrode potential $(E^{\circ})$. $A$ more negative $E^{\circ}$ value indicates a stronger reducing agent,while a less negative (or more positive) $E^{\circ}$ value indicates a weaker reducing agent.The standard electrode potentials $(E^{\circ})$ for the given alkali metals are as follows:Metal Ion/Metal$E^{\circ}$ (in Volts)$Li^{+}/Li$$-3.05$$Na^{+}/Na$$-2.71$$K^{+}/K$$-2.93$$Cs^{+}/Cs$$-2.92$Comparing the values,$Na$ has the least negative $E^{\circ}$ value $(-2.71 \ V)$. Therefore,$Na$ is the weakest reducing agent among the given options.

Which one of the following alkali metals is the weakest reducing agent as per their $E^{\circ}$ values?

Similar Questions

Sodium metal can be stored under

Among the following,which has the maximum hydration energy?

Sodium metal cannot be stored under

The hydration energy of $Mg^{2+}$ is

The characteristic not related to alkali metal is

Vedclass Test Series

Exam Paper Generator

Online Exam Module