Which one of the carbanions is the least stab | vedclass

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Question

(C) The stability of carbanions is determined by the electron-withdrawing or electron-donating nature of the groups attached to the negatively charged

Vedclass · Accepted Answer

$^{\ominus}CH_2-CH_3$

Vedclass · Answer

(C) The stability of carbanions is determined by the electron-withdrawing or electron-donating nature of the groups attached to the negatively charged carbon.Electron-withdrawing groups ($-NO_2$,$-CHO$) stabilize the carbanion by dispersing the negative charge.Electron-donating groups $(-CH_3)$ destabilize the carbanion by increasing the electron density on the negatively charged carbon.Comparing the given options:$1$. $^{\ominus}CH_2-NO_2$: $-NO_2$ is a strong electron-withdrawing group ($-I$ and $-M$ effect).$2$. $^{\ominus}CH_2-CHO$: $-CHO$ is an electron-withdrawing group ($-I$ and $-M$ effect).$3$. $^{\ominus}CH_2-CH_3$: $-CH_3$ is an electron-donating group ($+I$ effect).$4$. $^{\ominus}CH_3$: This is a methyl carbanion with no additional alkyl groups.Between $^{\ominus}CH_2-CH_3$ and $^{\ominus}CH_3$,the ethyl carbanion $(^{\ominus}CH_2-CH_3)$ is less stable due to the $+I$ effect of the additional methyl group,which increases electron density on the anionic center.

Which one of the carbanions is the least stable?

Similar Questions

Which of the following carbocations lacks hyperconjugative stability?

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Among the given species,which carbocations are resonance stabilized?

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