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(C) The Friedel-Crafts reaction is an electrophilic aromatic substitution. It requires an activated or moderately deactivated aromatic ring. $1$. $Ben

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Chlorobenzene

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(C) The Friedel-Crafts reaction is an electrophilic aromatic substitution. It requires an activated or moderately deactivated aromatic ring. $1$. $Benzamide$ has a strongly electron-withdrawing $-CONH_2$ group,which deactivates the ring. $2$. $Aniline$ $(-NH_2)$ and $Phenol$ $(-OH)$ contain lone pairs that react with the Lewis acid catalyst $(AlCl_3)$ to form a complex,which strongly deactivates the ring and prevents the reaction. $3$. $Chlorobenzene$ is a deactivated ring due to the $-I$ effect of the chlorine atom,but it is still capable of undergoing Friedel-Crafts reactions,unlike the other options which are either strongly deactivated or form complexes with the catalyst. Therefore,among the given choices,$Chlorobenzene$ will produce the highest yield.

Which of these will produce the highest yield in a Friedel-Crafts reaction?

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