Which of the options correctly represents the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The $-NO_2$ group is a strong electron-withdrawing group that exerts both $-I$ (inductive) and $-M$ (mesomeric) effects. These effects decrease th

Vedclass · Accepted Answer

$i > ii > iii$

Vedclass · Answer

(A) The $-NO_2$ group is a strong electron-withdrawing group that exerts both $-I$ (inductive) and $-M$ (mesomeric) effects. These effects decrease the electron density on the nitrogen atom of the $-NH_2$ group,thereby reducing its basicity. In compound $(i)$,there is no electron-withdrawing group,so it is the most basic. In compound $(ii)$,the $-NO_2$ group is at the meta position,exerting only the $-I$ effect. In compound $(iii)$,the $-NO_2$ group is at the para position,exerting both $-I$ and strong $-M$ effects,which significantly reduce the electron density on the nitrogen atom. Therefore,the basicity order is $(i) > (ii) > (iii)$.

Which of the options correctly represents the basicity order for these compounds?

Similar Questions

In the reaction $RNH_2 + CHCl_3 + 3KOH(alc.) \rightarrow A + 3KCl + 3H_2O$,the product $A$ can be converted back to $RNH_2$ by which process?

The correct order of decreasing basic strength of the given amines is:

Benzenediazonium chloride on reaction with phenol in weakly basic medium gives

Which among the following molecules has the lowest $pK_b$ value?

The following two reactions give the same foul-smelling product $Z$. $C_2H_5Cl \xrightarrow{X} Z$ and $C_2H_5CONH_2 \xrightarrow{Br_2, NaOH} Y \xrightarrow{CHCl_3/ethanolic KOH, \Delta} Z$. $X$ and $Z$,respectively,are:

Vedclass Test Series

Exam Paper Generator

Online Exam Module