Which of the following would be optically act | vedclass

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(C) molecule is optically active if it lacks a plane of symmetry,a center of symmetry,and an alternating axis of symmetry.$1$. $CH_2=C=CH_2$ (allene)

Vedclass · Accepted Answer

$CH_3-CH=C=CH-CH_3$

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(C) molecule is optically active if it lacks a plane of symmetry,a center of symmetry,and an alternating axis of symmetry.$1$. $CH_2=C=CH_2$ (allene) is achiral because it has a plane of symmetry.$2$. $4,4'$-difluorobiphenyl is achiral due to the presence of a plane of symmetry.$3$. $CH_3-CH=C=CH-CH_3$ (penta$-2,3-$diene) is chiral because the two terminal carbons have different groups attached,and the molecule lacks a plane of symmetry.$4$. The structure shown in option $D$ is $2,3$-dihydroxybutane. Depending on the configuration (e.g.,the $(2R, 3R)$ or $(2S, 3S)$ isomers),it can be optically active. However,in the context of comparing these specific choices,the allene derivative in $C$ is a classic example of axial chirality,while the structure in $D$ is a meso compound if it has an internal plane of symmetry. Given the specific Fischer projection provided,it represents a chiral molecule (specifically,the $(2R, 3R)$ or $(2S, 3S)$ form). Both $C$ and $D$ are optically active. Typically,in such multiple-choice questions,the most distinct example of chirality is sought. $C$ is definitely chiral. $D$ as drawn is also chiral.

$(I)$ Optical Activity	$(II)$ Form	$(III)$ Sign	$(IV)$ Rotation
$(A)$ Dextrorotatory	$d$	$(+)$	Right
$(B)$ Laevorotatory	$l$	$(-)$	Left
$(C)$ Optically Inactive (Racemic)	$dl$	$(\pm)$	Zero rotation

Which of the following would be optically active?

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