Which of the following would not give 2-pheny | vedclass

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(C) Friedel-Crafts alkylation of benzene with $n$-butyl chloride $(CH_3CH_2CH_2CH_2Cl)$ in the presence of $AlCl_3$ leads to rearrangement of the carb

Vedclass · Accepted Answer

$Butanoyl chloride + AlCl_3$ then $Zn, HCl$

Vedclass · Answer

(C) Friedel-Crafts alkylation of benzene with $n$-butyl chloride $(CH_3CH_2CH_2CH_2Cl)$ in the presence of $AlCl_3$ leads to rearrangement of the carbocation. The primary carbocation rearranges to a more stable secondary carbocation,resulting in $2-$phenylbutane as the major product. Similarly,$but-1-ene + HF$ and $butan-2-ol + H_2SO_4$ both generate the $sec-butyl$ carbocation,which yields $2-$phenylbutane. However,the reaction of $Butanoyl chloride + AlCl_3$ is a Friedel-Crafts acylation,which produces $1-$phenylbutan$-1-$one. Subsequent Clemmensen reduction $(Zn(Hg)/HCl)$ of this ketone yields $n$-butylbenzene ($1-$phenylbutane),not $2-$phenylbutane.

Which of the following would not give $2-$phenylbutane as the major product in a Friedel-Crafts alkylation reaction?

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