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(C) The dipole moment of a molecule depends on its geometry and the polarity of its bonds.$BF_3$ has a trigonal planar geometry,$SiF_4$ has a tetrahed

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$SF_4$

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(C) The dipole moment of a molecule depends on its geometry and the polarity of its bonds.$BF_3$ has a trigonal planar geometry,$SiF_4$ has a tetrahedral geometry,and $XeF_4$ has a square planar geometry. Due to their high symmetry,the bond dipoles in these molecules cancel each other out,resulting in a net dipole moment of zero.$SF_4$ has a see-saw geometry due to the presence of one lone pair on the sulfur atom. This lack of symmetry prevents the bond dipoles from canceling out,resulting in a permanent dipole moment.

List-$I$ (Molecules)	List-$II$ (Dipole moment)
$A$. $HBr$	$I$. $1.04$
$B$. $H_2S$	$II$. $0$
$C$. $NH_3$	$III$. $0.79$
$D$. $CHCl_3$	$IV$. $0.95$
	$V$. $1.47$

Which of the following would have a permanent dipole moment?

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Which of the following molecules has the highest dipole moment?

Match the following molecules in List-$I$ with their respective dipole moments in List-$II$.
List-$I$ (Molecules) List-$II$ (Dipole moment)
$A$. $HBr$ $I$. $1.04$
$B$. $H_2S$ $II$. $0$
$C$. $NH_3$ $III$. $0.79$
$D$. $CHCl_3$ $IV$. $0.95$
$V$. $1.47$

How can the charge distribution in iodine monochloride $(ICl)$ be represented?

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Which of the following would have a permanent dipole moment?

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Which of the following molecules is non-polar?

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Which of the following molecules has the highest dipole moment?

Match the following molecules in List-$I$ with their respective dipole moments in List-$II$.List-$I$ (Molecules)List-$II$ (Dipole moment)$A$. $HBr$$I$. $1.04$$B$. $H_2S$$II$. $0$$C$. $NH_3$$III$. $0.79$$D$. $CHCl_3$$IV$. $0.95$$V$. $1.47$

How can the charge distribution in iodine monochloride $(ICl)$ be represented?

Vedclass Test Series

Exam Paper Generator

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Match the following molecules in List-$I$ with their respective dipole moments in List-$II$.
List-$I$ (Molecules) List-$II$ (Dipole moment)
$A$. $HBr$ $I$. $1.04$
$B$. $H_2S$ $II$. $0$
$C$. $NH_3$ $III$. $0.79$
$D$. $CHCl_3$ $IV$. $0.95$
$V$. $1.47$