Which of the following will not be soluble in sodium hydrogen carbonate?

The product of the following reaction is $P$.
$4-hydroxybenzaldehyde + PhMgBr (1 \text{ equiv.}) \xrightarrow{aq. NH_4Cl} P$
The number of hydroxyl groups present in the product $P$ is . . . . . . .

Phenol $\xrightarrow[(ii) CO_2 / 140^{\circ}C]{(i) NaOH} A$ $\xrightarrow{H^{+} / H_2O} B$ $\xrightarrow[CH_3COOH, \Delta]{Al_2O_3} C$
In this reaction,the end product $C$ is :

Choose the incorrect option based on the reaction:
$(P)$ + $CH_3-CO-Cl \rightarrow (Q)$
Where $(P)$ is salicylic acid and the structure of $(Q)$ is given as:
$(Q)$ is a benzene ring with an $-OH$ group and a $-COO-CO-CH_3$ group at ortho position.

Phenol $\stackrel{X}{\longrightarrow}$ forms a tribromo derivative. "$X$" is

In which of the following,ortho/para substitution by an electrophile is very facile?