Which of the following will have two stereois | vedclass

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(B) To determine the number of stereoisomeric forms:$I. [Cr(NO_3)_3(NH_3)_3]$ is of the type $MA_3B_3$. It exhibits facial $(fac)$ and meridional $(me

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$I$ and $II$

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(B) To determine the number of stereoisomeric forms:$I. [Cr(NO_3)_3(NH_3)_3]$ is of the type $MA_3B_3$. It exhibits facial $(fac)$ and meridional $(mer)$ isomers. Thus,it has $2$ stereoisomers.$II. K_3[Fe(C_2O_4)_3]$ is of the type $M(AA)_3$. It exists as a pair of enantiomers ($d$ and $l$ forms). Thus,it has $2$ stereoisomers.$III. [CoCl_2(en)_2]^+$ is of the type $M(AA)_2B_2$. It exhibits $cis$ and $trans$ isomers. The $cis$ form is optically active ($d$ and $l$ forms),while the $trans$ form is optically inactive. Thus,it has $3$ stereoisomers.$IV. [CoBrCl(ox)_2]^{3-}$ is of the type $M(AA)_2BC$. It exhibits $cis$ and $trans$ isomers. The $cis$ form is optically active ($d$ and $l$ forms),while the $trans$ form is optically inactive. Thus,it has $3$ stereoisomers.Therefore,only $I$ and $II$ have exactly $2$ stereoisomeric forms.

Column-$I$	Column-$II$
$(a) [Pt(NH_3)_3Cl]Br$	$(P) \text{Coordination isomerism}$
$(b) [Cr(NH_3)_5(NCS)]^{+2}$	$(Q) \text{Ionisation isomerism}$
$(c) [Co(H_2O)_6]Cl_3$	$(R) \text{Linkage isomerism}$
$(d) [PtCl_4][Pt(NH_3)_4]$	$(S) \text{Hydrate isomerism}$

Which of the following will have two stereoisomeric forms?
$I. [Cr(NO_3)_3(NH_3)_3]$
$II. K_3[Fe(C_2O_4)_3]$
$III. [CoCl_2(en)_2]^+$
$IV. [CoBrCl(ox)_2]^{3-}$

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Which of the following compounds does not show optical activity?

Match the column:
Column-$I$ Column-$II$
$(a) [Pt(NH_3)_3Cl]Br$ $(P) \text{Coordination isomerism}$
$(b) [Cr(NH_3)_5(NCS)]^{+2}$ $(Q) \text{Ionisation isomerism}$
$(c) [Co(H_2O)_6]Cl_3$ $(R) \text{Linkage isomerism}$
$(d) [PtCl_4][Pt(NH_3)_4]$ $(S) \text{Hydrate isomerism}$

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Which of the following will have two stereoisomeric forms?$I. [Cr(NO_3)_3(NH_3)_3]$$II. K_3[Fe(C_2O_4)_3]$$III. [CoCl_2(en)_2]^+$$IV. [CoBrCl(ox)_2]^{3-}$