Which of the following will have maximum stab | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The crystal field stabilization energy $(CFSE)$ depends on the nature of the ligand and the oxidation state of the metal ion.
$CN^-$ is a strong

Vedclass · Accepted Answer

$[Co(CN)_6]^{3-}$

Vedclass · Answer

(C) The crystal field stabilization energy $(CFSE)$ depends on the nature of the ligand and the oxidation state of the metal ion.
$CN^-$ is a strong field ligand,which causes a large splitting of $d$-orbitals $(\Delta_o)$.
In $[Co(CN)_6]^{3-}$,$Co$ is in the $+3$ oxidation state ($d^6$ configuration).
Since $CN^-$ is a strong field ligand,it leads to a low-spin $t_{2g}^6 e_g^0$ configuration,resulting in a very high $CFSE$ value compared to the other complexes listed,which involve weak field ligands like $H_2O$ or have lower oxidation states.

Which of the following will have maximum stabilization due to crystal field?

Similar Questions

Why are low spin tetrahedral complexes not formed?

Which of the following is the correct order of increasing field strength of ligands to form coordination compounds?

Value of $CFSE$,in a tetrahedral complex having $3d^4$ configuration of metal ion,surrounded by weak field ligands,will be

The electronic configuration of the central metal atom/ion in $\left[ Co(CN)_6 \right]^{3-}$ is

Which among the following is a correct order of increasing field strength of ligands?

Vedclass Test Series

Exam Paper Generator

Online Exam Module