Which of the following will form an ideal solution?

Which of the following mixtures does not show positive deviation from Raoult's law?

Which of the following liquid pairs shows a positive deviation from Raoult's law?

$A$ mixture of toluene and benzene boils at $100^{\circ} C$. Assuming ideal behaviour,the mole fraction of toluene in the mixture is closest to (Vapour pressures of pure toluene and pure benzene at $100^{\circ} C$ are $0.742 \ bar$ and $1.800 \ bar$,respectively. $1 \ atm = 1.013 \ bar$)

$A$ solution of two miscible liquids showing negative deviation from Raoult's law will have :

$1 \ mol$ of liquid $A$ and $2 \ mol$ of liquid $B$ make a solution having an observed vapour pressure of $42 \ torr$. The vapour pressures of pure $A$ and pure $B$ are $45 \ torr$ and $36 \ torr$ respectively. The described solution: