Which of the following substances acts as bot | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) In $NaNO_2$ (Sodium nitrite),the oxidation state of nitrogen $(N)$ is $+3$. Nitrogen can be oxidized to a higher oxidation state (e.g.,$+5$ in $NO

Vedclass · Accepted Answer

$NaNO_2$

Vedclass · Answer

(D) In $NaNO_2$ (Sodium nitrite),the oxidation state of nitrogen $(N)$ is $+3$. Nitrogen can be oxidized to a higher oxidation state (e.g.,$+5$ in $NO_3^-$) or reduced to a lower oxidation state (e.g.,$+2, +1, 0, -3$). Therefore,$NaNO_2$ can act as both an oxidizing agent and a reducing agent. In $NaNO_3$,$N$ is in its maximum oxidation state $(+5)$,so it acts only as an oxidizing agent. In $Na_2O$,$O$ is in its minimum oxidation state $(-2)$,so it acts only as a reducing agent. In $Na_2O_2$,$O$ is in $-1$ state,which can be oxidized to $0$ or reduced to $-2$,but $NaNO_2$ is the classic example of a substance showing dual behavior due to the intermediate oxidation state of nitrogen.

Which of the following substances acts as both an oxidizing agent and a reducing agent?

Similar Questions

Identify the pair of reactions undergoing disproportionation from the following.

In the following reaction $P_4 + 3NaOH + 3H_2O \to PH_3 + 3NaH_2PO_2$,what happens to phosphorus?

$3NaClO \xrightarrow{\Delta} NaClO_3 + 2NaCl$
Which of the following is true for the given reaction?

Assign $A$,$B$,$C$,$D$ from the given type of reaction.
$Ca(OH)_2 + Cl_2 \longrightarrow CaOCl_2 + H_2O$

Which of the following does not show a disproportionation reaction?

Vedclass Test Series

Exam Paper Generator

Online Exam Module