Which of the following statements is correct?

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(D) In $[CoF_6]^{3-}$,the oxidation state of $Co$ is $+3$ ($3d^6$ configuration). $F^-$ is a weak field ligand,so it forms an outer orbital complex ($

Vedclass · Accepted Answer

$[CoF_6]^{3-}$ is outer orbital complex while $[Co(NH_3)_6]^{3+}$ is inner orbital complex

Vedclass · Answer

(D) In $[CoF_6]^{3-}$,the oxidation state of $Co$ is $+3$ ($3d^6$ configuration). $F^-$ is a weak field ligand,so it forms an outer orbital complex ($sp^3d^2$ hybridization) which is paramagnetic with $4$ unpaired electrons.In $[Co(NH_3)_6]^{3+}$,the oxidation state of $Co$ is $+3$ ($3d^6$ configuration). $NH_3$ is a strong field ligand,so it causes pairing of electrons,forming an inner orbital complex ($d^2sp^3$ hybridization) which is diamagnetic.Therefore,statement $D$ is correct: $[CoF_6]^{3-}$ is an outer orbital complex while $[Co(NH_3)_6]^{3+}$ is an inner orbital complex.

Similar Questions

Which of the following statements is correct regarding the complexes $[CoF_6]^{3-}$ and $[Co(NH_3)_6]^{3+}$?

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The coordination complex $[Co(OH_2)_6]^{2+}$ has one unpaired electron. Which of the following statements are true?
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Which of the following complexes exhibits outer orbital hybridization?

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