Which of the following statements is correct?

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(B) The second electron affinity is always endothermic (positive) because an electron is added to a negatively charged ion,leading to inter-electronic

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The magnitude of the second electron affinity of sulphur is less than that of oxygen

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(B) The second electron affinity is always endothermic (positive) because an electron is added to a negatively charged ion,leading to inter-electronic repulsion. For oxygen $(O^-)$,the electron is added to a smaller $2p$ orbital,resulting in higher repulsion compared to sulphur $(S^-)$ where the electron is added to a larger $3p$ orbital. Therefore,the magnitude of the second electron affinity of sulphur is less than that of oxygen. Additionally,the first electron affinity of chlorine is greater than that of fluorine due to the small size and high inter-electronic repulsion in the $2p$ subshell of fluorine. The correct order is $Cl > F > Br > I$.

List-$I$ (Element)	List-$II$ ($\Delta_{eg}H$ in $kJ \ mol^{-1}$)
$A$. $O$	$I$. $-200$
$B$. $F$	$II$. $-349$
$C$. $Cl$	$III$. $-141$
$D$. $S$	$IV$. $-328$
	$V$. $+48$

Similar Questions

If the electron affinity of $Cl$ is $348 \ kJ/mol$,then how much energy is released to convert $1.0 \ g$ of $Cl$ into $Cl^-$ gas in $kJ$?

The value of $2^{nd}$ electron gain enthalpy for $O$ and $S$ will be (in $kJ/mol$)

In which of the following processes is energy absorbed?

Which of the following arrangements for the three halogens $Cl$,$Br$,and $I$ when placed in the order of their increasing electron affinity is correct?

Match the following:
List-$I$ (Element) List-$II$ ($\Delta_{eg}H$ in $kJ \ mol^{-1}$)
$A$. $O$ $I$. $-200$
$B$. $F$ $II$. $-349$
$C$. $Cl$ $III$. $-141$
$D$. $S$ $IV$. $-328$
$V$. $+48$

The correct answer is:

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