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(C) The peroxide ion is $O_{2}^{2-}$.Electronic configuration: $O_{2}^{2-} (18 	ext{ electrons}) = \sigma 1s^{2}, \sigma^{*} 1s^{2}, \sigma 2s^{2}, \

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$(i)$,$(ii)$ and $(iii)$

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(C) The peroxide ion is $O_{2}^{2-}$.Electronic configuration: $O_{2}^{2-} (18 	ext{ electrons}) = \sigma 1s^{2}, \sigma^{*} 1s^{2}, \sigma 2s^{2}, \sigma^{*} 2s^{2}, \sigma 2p_{z}^{2}, \pi 2p_{x}^{2} \approx \pi 2p_{y}^{2}, \pi^{*} 2p_{x}^{2} \approx \pi^{*} 2p_{y}^{2}$.Bond order $= \frac{N_{b} - N_{a}}{2} = \frac{10 - 8}{2} = 1$.It contains four completely filled antibonding molecular orbitals $(\sigma^{*} 1s, \sigma^{*} 2s, \pi^{*} 2p_{x}, \pi^{*} 2p_{y})$.Since all electrons are paired,$O_{2}^{2-}$ is diamagnetic.It has $18$ electrons,so it is isoelectronic with argon $(18)$,not neon $(10)$.

Which of the following statements are correct for the peroxide ion $(O_{2}^{2-})$?
$(i)$ It has a bond order of $1$.
$(ii)$ It is diamagnetic.
$(iii)$ It has four completely filled antibonding molecular orbitals.
$(iv)$ It is isoelectronic with neon.

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Which of the following statements are correct for the peroxide ion $(O_{2}^{2-})$?$(i)$ It has a bond order of $1$.$(ii)$ It is diamagnetic.$(iii)$ It has four completely filled antibonding molecular orbitals.$(iv)$ It is isoelectronic with neon.