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(A) The reaction between copper and dilute $HNO_3$ is given by:$3Cu + 8HNO_3 \rightarrow 3Cu(NO_3)_2 + 2NO + 4H_2O$$(I)$ The principal reduction produ

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$I, II, III$

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(A) The reaction between copper and dilute $HNO_3$ is given by:$3Cu + 8HNO_3 \rightarrow 3Cu(NO_3)_2 + 2NO + 4H_2O$$(I)$ The principal reduction product is $NO$ gas. This is correct.$(II)$ $Cu$ metal is oxidized to $Cu^{2+}$ (aq.) ion,which is blue in color. This is correct.$(III)$ $NO$ has $15$ electrons. Its molecular orbital configuration is $\sigma_{1s}^2 \sigma_{1s}^{*2} \sigma_{2s}^2 \sigma_{2s}^{*2} \sigma_{2p_z}^2 \pi_{2p_x}^2 \pi_{2p_y}^2 \pi_{2p_x}^{*1}$. It is paramagnetic and has one unpaired electron in the antibonding molecular orbital. This is correct.$(IV)$ $NO$ reacts with $O_2$ to produce $NO_2$ $(2NO + O_2 \rightarrow 2NO_2)$. $NO_2$ is a bent molecule,not linear. This statement is incorrect.Therefore,statements $(I), (II),$ and $(III)$ are correct.

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