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(D) In the Bohr model,the potential energy $(P.E.)$ of an electron in the $n^{	ext{th}}$ orbit is given by $P.E. = -\frac{kZe^2}{r_n}$. Since $r_n \p

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Potential energy of electron in $n=2$ orbit is less than that in $n=1$ orbit.

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(D) In the Bohr model,the potential energy $(P.E.)$ of an electron in the $n^{	ext{th}}$ orbit is given by $P.E. = -\frac{kZe^2}{r_n}$. Since $r_n \propto n^2$,we have $P.E. \propto -\frac{1}{n^2}$.As $n$ increases,the magnitude of the negative potential energy decreases,meaning the value becomes less negative (i.e.,it increases).For $n=1$,$P.E. = -27.2 	ext{ eV}$.For $n=2$,$P.E. = -6.8 	ext{ eV}$.Since $-6.8 	ext{ eV} > -27.2 	ext{ eV}$,the potential energy in the $n=2$ orbit is greater than in the $n=1$ orbit.Therefore,the statement in option $D$ is false.

Which of the following statements about the Bohr model of the hydrogen atom is false?

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