Which of the following statements about prima | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $(i)$ The presence of an electron-withdrawing substituent decreases basicity,while the presence of an electron-releasing substituent like $-CH_{3}

Vedclass · Accepted Answer

Aryl amines react with nitrous acid to produce phenols.

Vedclass · Answer

(C) $(i)$ The presence of an electron-withdrawing substituent decreases basicity,while the presence of an electron-releasing substituent like $-CH_{3}, -C_{2}H_{5},$ etc.,increases basicity.$(ii)$ $HNO_{2}$ converts the $-NH_{2}$ group of aliphatic amines into $-OH$ (alcohols),whereas it converts aromatic amines into diazonium salts at low temperatures $(0-5\,^{\circ}C)$.$(iii)$ Alkyl amines are more basic than ammonia due to the electron-releasing effect of the alkyl group,while aryl amines are less basic than ammonia due to the electron-withdrawing nature of the phenyl ring.$(iv)$ The reaction for alkyl amines: $R-NH_{2} \xrightarrow{HNO_{2}} R-OH + N_{2} + H_{2}O$.$(v)$ The reaction for aryl amines: $C_{6}H_{5}NH_{2} \xrightarrow{NaNO_{2} + HCl, 273-278\,K} C_{6}H_{5}N_{2}^{+}Cl^{-}$.Therefore,the statement that aryl amines react with nitrous acid to produce phenols is false,as they form diazonium salts under these conditions.

Which of the following statements about primary amines is false?

Similar Questions

$X \ g$ of ethylamine is subjected to reaction with $NaNO_2 / HCl$ followed by water; evolved dinitrogen gas which occupied $2.24 \ L$ volume at $STP$. $X$ is . . . . . . $\times 10^{-1} \ g$.

Benzene diazonium chloride on reaction with ethanol forms

Identify product $A$ in the following reaction:
$C_6H_5N_2^+Cl^- \xrightarrow{C_2H_5OH} A + N_2 + CH_3CHO + HCl$

Identify $X$ and $Y$ in the following reactions:
$Nitrobenzene \xrightarrow{Zn/NH_4Cl} X$
$Nitrobenzene \xrightarrow{Zn + KOH/C_2H_5OH} Y$

An organic compound $[A]$ $(C_4H_{11}N)$ shows optical activity and gives $N_2$ gas on treatment with $HNO_2$. The compound $[A]$ reacts with $PhSO_2Cl$ producing a compound which is soluble in $KOH$. The structure of $A$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module