Which of the following statements is correct?

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(D) Option $(A)$ is incorrect because a charged particle entering a magnetic field at an angle other than $90^o$ follows a helical path,not a circular

Vedclass · Accepted Answer

Both $(B)$ and $(C)$

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(D) Option $(A)$ is incorrect because a charged particle entering a magnetic field at an angle other than $90^o$ follows a helical path,not a circular one.Option $(B)$ is correct. When a charged particle enters a uniform magnetic field perpendicular to its velocity,it experiences a magnetic force $F = q(v 	imes B)$ which acts as a centripetal force,causing the particle to move in a circular path. Both the electron and proton will follow circular paths.Option $(C)$ is correct. The magnetic force acting on a moving charged particle is always perpendicular to its velocity $(F = q(v 	imes B))$. Since the force is perpendicular to the displacement,the work done by the magnetic force is zero $(W = F \cdot ds = 0)$. According to the work-energy theorem,the kinetic energy of the particle remains constant.Since both $(B)$ and $(C)$ are correct,option $(D)$ is the correct answer.

Column $I$	Column $II$
$(A)$ Two parallel wires with current in the same direction,$P$ is the midpoint.	$(p)$ The magnetic fields $(B)$ at $P$ due to the currents in the wires are in the same direction.
$(B)$ Two coaxial circular loops with current in the same direction,$P$ is the midpoint on the axis.	$(q)$ The magnetic fields $(B)$ at $P$ due to the currents in the wires are in opposite directions.
$(C)$ Two coplanar circular loops with current in opposite directions,$P$ is the midpoint.	$(r)$ There is no magnetic field at $P$.
$(D)$ Two concentric coplanar circular loops with current in the same direction,$P$ is the common center.	$(s)$ The wires repel each other.

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