Which of the following species would not be i | vedclass

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(D) The Hoffmann rearrangement involves the following steps:$1$. Formation of $N$-bromamide by the reaction of amide with $Br_2$ and $NaOH$.$2$. Forma

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All of the above are involved in the reaction.

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(D) The Hoffmann rearrangement involves the following steps:$1$. Formation of $N$-bromamide by the reaction of amide with $Br_2$ and $NaOH$.$2$. Formation of an acyl nitrene or direct rearrangement of the $N$-bromoamide anion to an isocyanate.$3$. The isocyanate is then hydrolyzed to the amine.Looking at the provided mechanism in the solution image,the species involved are:$(a)$ $N$-bromocyclohexanecarboxamide$(b)$ The conjugate base of the $N$-bromoamide$(c)$ Cyclohexyl isocyanateSince all these species are intermediates or products in the mechanism of the Hoffmann rearrangement,option $D$ is the correct answer.

List-$I$	List-$II$
$A$. Benzenesulphonyl chloride	$I$. Test for primary amines
$B$. Hoffmann bromamide reaction	$II$. Anti Saytzeff
$C$. Carbylamine reaction	$III$. Hinsberg reagent
$D$. Hoffmann orientation	$IV$. Known reaction of isocyanates

Which of the following species would not be involved in the Hoffmann rearrangement shown below?

Similar Questions

Benzyl isocyanide can be obtained from which of the following reactions? Choose the correct answer from the options given below:
$A$. Benzyl bromide + $AgCN$
$B$. Benzylamine + $CHCl_3$ + $Aq. NaOH$
$C$. Bromobenzene + $AgCN$
$D$. Aniline + $CHCl_3$ + $Aq. NaOH$
$E$. $2-$Phenylethyl bromide + $KCN$

What are $X$ and $Y$ respectively in the following set of reactions?

Give a plausible explanation for each of the following:
$(i)$ Why are amines less acidic than alcohols of comparable molecular masses?
$(ii)$ Why do primary amines have higher boiling points than tertiary amines?
$(iii)$ Why are aliphatic amines stronger bases than aromatic amines?

From $6.55 \ g$ of aniline,the maximum amount of acetanilide that can be prepared will be _ $\times 10^{-1} \ g$.

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