Which of the following salts has the same val | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The Van't Hoff factor $i$ represents the number of particles a solute dissociates into in a solution.For $K_4[Fe(CN)_6]$,the dissociation is: $K_4

Vedclass · Accepted Answer

$Al_2(SO_4)_3$

Vedclass · Answer

(A) The Van't Hoff factor $i$ represents the number of particles a solute dissociates into in a solution.For $K_4[Fe(CN)_6]$,the dissociation is: $K_4[Fe(CN)_6] \rightarrow 4K^{+} + [Fe(CN)_6]^{4-}$.Total number of particles $i = 4 + 1 = 5$.Now,checking the options:$A$. $Al_2(SO_4)_3 \rightarrow 2Al^{3+} + 3SO_4^{2-}$,so $i = 2 + 3 = 5$.$B$. $NaCl \rightarrow Na^{+} + Cl^{-}$,so $i = 1 + 1 = 2$.$C$. $Na_2SO_4 \rightarrow 2Na^{+} + SO_4^{2-}$,so $i = 2 + 1 = 3$.$D$. $Al(NO_3)_3 \rightarrow Al^{3+} + 3NO_3^{-}$,so $i = 1 + 3 = 4$.Therefore,$Al_2(SO_4)_3$ has the same Van't Hoff factor as $K_4[Fe(CN)_6]$.

Which of the following salts has the same value of Van't Hoff factor $i$ as that of $K_4[Fe(CN)_6]$?

Similar Questions

Assuming $100\%$ ionization,the correct order of freezing point for the following solutions is:

If for a sucrose solution the elevation in boiling point is $0.1\,^{\circ}C$,then what will be the elevation in boiling point of a $NaCl$ solution for the same molal concentration? (in $^{\circ}C$)

Which of the following aqueous solutions has the highest boiling point?

The freezing point depression constant for water is $1.86 \, ^oC \, kg \, mol^{-1}.$ If $5.00 \, g$ of $Na_2SO_4$ is dissolved in $45.0 \, g$ of $H_2O,$ the freezing point is lowered by $3.82 \, ^oC.$ Calculate the van't Hoff factor for $Na_2SO_4.$

Explain the van't Hoff factor and provide its formula.

Vedclass Test Series

Exam Paper Generator

Online Exam Module