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Question

(D) For a $4d$ electron,the principal quantum number $n = 4$.For a $d$-orbital,the azimuthal quantum number $l = 2$.The magnetic quantum number $m$ ca

Vedclass · Accepted Answer

$n=4, l=2, m=1, s=-1/2$

Vedclass · Answer

(D) For a $4d$ electron,the principal quantum number $n = 4$.For a $d$-orbital,the azimuthal quantum number $l = 2$.The magnetic quantum number $m$ can have any integer value from $-l$ to $+l$,i.e.,$-2, -1, 0, +1, +2$.The spin quantum number $s$ can be either $+1/2$ or $-1/2$.Comparing this with the given options,option $D$ $(n=4, l=2, m=1, s=-1/2)$ satisfies all the conditions for a $4d$ electron.

Which of the following represents the correct set of four quantum numbers for a $4d$ electron?

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