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(A) The rate of $S_N2$ reaction is inversely proportional to the steric hindrance around the reaction center.As the number of alkyl groups attached to

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(A) The rate of $S_N2$ reaction is inversely proportional to the steric hindrance around the reaction center.As the number of alkyl groups attached to the carbon bearing the leaving group increases (i.e.,from methyl to tertiary),the steric hindrance increases,which significantly decreases the rate of the $S_N2$ reaction.Therefore,$\log(	ext{rate})$ decreases as we move from $CH_3Br$ to $t-BuBr$.The correct graph is the one showing a downward trend.

Which of the following represents the correct graph for $S_N2$ reaction?

Similar Questions

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