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(A) $But-1-yne$ $(CH_3CH_2C \equiv CH)$ contains a terminal acidic hydrogen atom attached to an $sp$ hybridized carbon atom.$But-2-yne$ $(CH_3C \equiv

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$NaNH_2$

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(A) $But-1-yne$ $(CH_3CH_2C \equiv CH)$ contains a terminal acidic hydrogen atom attached to an $sp$ hybridized carbon atom.$But-2-yne$ $(CH_3C \equiv CCH_3)$ does not have any terminal acidic hydrogen atom.$NaNH_2$ is a strong base that can abstract the acidic proton from $but-1-yne$ to form a sodium acetylide salt,whereas $but-2-yne$ does not react with $NaNH_2$.Reaction: $CH_3CH_2C \equiv CH + NaNH_2 \rightarrow CH_3CH_2C \equiv C^-Na^+ + NH_3$.Therefore,$NaNH_2$ is the correct reagent to distinguish between them.

Which of the following reagents will be able to distinguish between $but-1-yne$ and $but-2-yne$?

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