Which of the following reactions will yield 2 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction of propyne $(CH_3C \equiv CH)$ with two equivalents of hydrogen bromide $(HBr)$ follows Markovnikov's rule. In the first step,$HBr$ a

Vedclass · Accepted Answer

$CH_3C \equiv CH + 2HBr \rightarrow$

Vedclass · Answer

(B) The reaction of propyne $(CH_3C \equiv CH)$ with two equivalents of hydrogen bromide $(HBr)$ follows Markovnikov's rule. In the first step,$HBr$ adds to the triple bond to form $2-$bromopropene $(CH_3C(Br)=CH_2)$. In the second step,another molecule of $HBr$ adds to the double bond,again following Markovnikov's rule,to yield $2, 2-$dibromopropane $(CH_3C(Br)_2CH_3)$.

Which of the following reactions will yield $2, 2-$dibromopropane?

Similar Questions

$CH \equiv CH + HBr \to X$,the product $X$ is:

Acetylene reacts with a $42\% H_2SO_4$ solution containing $1\% HgSO_4$ to give

$CH \equiv CH$ $\xrightarrow[H_2SO_4]{H_2O/Hg^{2+}} X$ $\xrightarrow{LiAlH_4} Y$ $\xrightarrow{P_4/Br_2} Z$. Here $Z$ is

Which of the following reactions forms an aldehyde as a product?

This conversion can be achieved by:

Vedclass Test Series

Exam Paper Generator

Online Exam Module