(A) The Rosenmund reduction is a hydrogenation process where an acyl chloride $(R-COCl)$ is reduced to an aldehyde $(R-CHO)$ using hydrogen gas in the

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$R-COCl + H_2 \xrightarrow{Pd-BaSO_4} R-CHO + HCl$

(A) The Rosenmund reduction is a hydrogenation process where an acyl chloride $(R-COCl)$ is reduced to an aldehyde $(R-CHO)$ using hydrogen gas in the presence of a poisoned palladium catalyst,specifically palladium on barium sulfate $(Pd-BaSO_4)$.The reaction is represented as:$R-COCl + H_2 \xrightarrow{Pd-BaSO_4} R-CHO + HCl$Therefore,option $A$ represents the Rosenmund reduction.

Class 12 Chemistry 8-1.Aldehydes and Ketones Preparation

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Which of the following reactions is Rosenmund reduction?

MHT CET 2023 All MHT CET

A
$R-COCl + H_2 \xrightarrow{Pd-BaSO_4} R-CHO + HCl$
B
$R-CN \xrightarrow{SnCl_2, HCl} R-CHO + NH_4Cl$
C
$R-CHO \xrightarrow{Zn-Hg, \text{conc. } HCl} R-CH_3 + H_2O$
D
$Ar-CH_3 \xrightarrow{CrO_2Cl_2, CS_2} Ar-CHO$

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8-1.Aldehydes and Ketones

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Match List-$I$ with List-$II$.
List-$I$ (Reagents) List-$II$ (Reaction Name)
$A$. $H_2, Pd-BaSO_4$ $I$. Etard Reaction
$B$. $SnCl_2, HCl$ $II$. Rosenmund Reduction
$C$. $CrO_2Cl_2, CS_2$ $III$. Gatterman-Koch Reaction
$D$. $CO, HCl, \text{Anhyd. } AlCl_3$ $IV$. Stephen Reaction

Choose the correct answer from the options given below:

List-$I$ (Reagents)	List-$II$ (Reaction Name)
$A$. $H_2, Pd-BaSO_4$	$I$. Etard Reaction
$B$. $SnCl_2, HCl$	$II$. Rosenmund Reduction
$C$. $CrO_2Cl_2, CS_2$	$III$. Gatterman-Koch Reaction
$D$. $CO, HCl, \text{Anhyd. } AlCl_3$	$IV$. Stephen Reaction

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