Which of the following reactions will produce | vedclass

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(B, D) $1$. Hydration of propene $(CH_3-CH=CH_2)$ with dilute $H_2SO_4$ follows Markovnikov's rule to give propan$-2-$ol (secondary alcohol).$2$. Hydr

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Catalytic reduction of butanal

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(B, D) $1$. Hydration of propene $(CH_3-CH=CH_2)$ with dilute $H_2SO_4$ follows Markovnikov's rule to give propan$-2-$ol (secondary alcohol).$2$. Hydroboration-oxidation of propene $(CH_3-CH=CH_2)$ with $BH_3$ followed by $H_2O_2/OH^-$ follows anti-Markovnikov's rule to give propan$-1-$ol (primary alcohol).$3$. Reaction of propanone $(CH_3COCH_3)$ with $CH_3MgBr$ followed by hydrolysis gives $2-$methylpropan$-2-$ol (tertiary alcohol).$4$. Catalytic reduction of butanal $(CH_3CH_2CH_2CHO)$ with $H_2/Ni$ gives butan$-1-$ol (primary alcohol).Both options $B$ and $D$ produce primary alcohols. However,in standard multiple-choice contexts where only one is expected,both are chemically valid. Given the phrasing,both are correct.

Which of the following reactions will produce a primary alcohol?

Similar Questions

$(i)$ Draw the structures of all isomeric alcohols of molecular formula $C_5H_{12}O$ and give their $IUPAC$ names.
$(ii)$ Classify the isomers of alcohols in question $(i)$ as primary,secondary and tertiary alcohols.

How are the following conversions carried out?
$(i)$ Propene $\rightarrow$ Propan$-2-$ol.
$(ii)$ Benzyl chloride $\rightarrow$ Benzyl alcohol.
$(iii)$ Ethyl magnesium chloride $\rightarrow$ Propan$-1-$ol.
$(iv)$ Methyl magnesium bromide $\rightarrow$ $2-$Methylpropan$-2-$ol.

Which of the following statements is correct?

Major product of the reaction is

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