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(B) The Rosenmund reduction involves the partial reduction of an acid chloride to an aldehyde using hydrogen gas over palladium poisoned with barium s

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$CH_3COCl \xrightarrow{H_2, Pd/BaSO_4}$

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(B) The Rosenmund reduction involves the partial reduction of an acid chloride to an aldehyde using hydrogen gas over palladium poisoned with barium sulfate $(Pd/BaSO_4)$.Aldehydes are carbonyl compounds.In option $(a)$,$H_2/Pd$ reduces the acid chloride further to a primary alcohol.In option $(c)$,$LiAlH_4$ is a strong reducing agent that reduces acid chlorides to primary alcohols.Therefore,only the Rosenmund reduction produces an aldehyde (a carbonyl compound) as the major product.

$A$. $C_6H_5COCl + H_2 \xrightarrow{Pd-BaSO_4} C_6H_5CHO$	$I$. Gattermann-Koch reaction
$B$. $CH_3CN + SnCl_2 + HCl \rightarrow CH_3CHO$	$II$. Etard reaction
$C$. $C_6H_5CH_3 + CrO_2Cl_2 \rightarrow C_6H_5CHO$	$III$. Stephen reaction
$D$. $C_6H_6 + CO + HCl \xrightarrow{AlCl_3} C_6H_5CHO$	$IV$. Rosenmund reaction

List-$I$ (Reagents)	List-$II$ (Reaction Name)
$A$. $H_2, Pd-BaSO_4$	$I$. Etard Reaction
$B$. $SnCl_2, HCl$	$II$. Rosenmund Reduction
$C$. $CrO_2Cl_2, CS_2$	$III$. Gatterman-Koch Reaction
$D$. $CO, HCl, \text{Anhyd. } AlCl_3$	$IV$. Stephen Reaction

Which of the following reactions will give a carbonyl compound as the major product?

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