Which of the following reactions does not involve the Hoffmann Bromamide degradation?

  • A
    $C_6H_5CH_2CONH_2 \xrightarrow{Br_2, NaOH} C_6H_5CH_2NH_2$
  • B
    $C_6H_5CN \xrightarrow[ii) Br_2, NaOH]{i) KOH, H_2O} C_6H_5NH_2$
  • C
    $C_6H_5CH_2COCH_3 \xrightarrow[iii) LiAlH_4, H_2O]{i) Br_2, NaOH/H^+, ii) NH_3/\Delta} C_6H_5CH_2CH_2NH_2$
  • D
    $C_6H_5COCl \xrightarrow[ii) Br_2, NaOH]{i) NH_3, NaOH} C_6H_5NH_2$

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Similar Questions

Identify the correct statements:
$(A)$ Primary amines do not give diazonium salts when treated with $NaNO_2$ in acidic conditions.
$(B)$ Aliphatic and aromatic primary amines on heating with $CHCl_3$ and ethanolic $KOH$ form carbylamines.
$(C)$ Secondary and tertiary amines also give the carbylamine test.
$(D)$ Benzenesulfonyl chloride is known as Hinsberg's reagent.
$(E)$ Tertiary amines react with benzenesulfonyl chloride very easily.
Choose the correct answer from the options given below:

By the presence of a halogen atom in the ring,the basic properties of aniline are:

On hydrolysis of a "compound",two compounds are obtained. One of which on treatment with sodium nitrite and hydrochloric acid gives a product which does not respond to iodoform test. The second one reduces Tollens reagent and Fehling's solution. The "compound" is

$o$-Phenylenediamine $\stackrel{HNO_2}{\longrightarrow}$ '$X$'

Which of the following is most basic?

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