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(D) $SO_2$ acts as a reducing agent in the presence of moisture.$I$. $SO_2$ reduces $O_3$ to $O_2$: $SO_2 + O_3 	o SO_3 + O_2$.$II$. $SO_2$ reduces a

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$I, II, III$

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(D) $SO_2$ acts as a reducing agent in the presence of moisture.$I$. $SO_2$ reduces $O_3$ to $O_2$: $SO_2 + O_3 	o SO_3 + O_2$.$II$. $SO_2$ reduces acidic dichromate $(Cr_2O_7^{2-})$ to $Cr^{3+}$: $Cr_2O_7^{2-} + 3SO_2 + 2H^+ 	o 2Cr^{3+} + 3SO_4^{2-} + H_2O$.$III$. $SO_2$ reduces acidic permanganate $(MnO_4^-)$ to $Mn^{2+}$: $2MnO_4^- + 5SO_2 + 2H_2O 	o 2Mn^{2+} + 5SO_4^{2-} + 4H^+$.$IV$. $H_2S$ is a reducing agent itself and is oxidized by $SO_2$ to $S$: $2H_2S + SO_2 	o 3S + 2H_2O$.Since $SO_2$ reduces $O_3$,$Cr_2O_7^{2-}$,and $MnO_4^-$,the correct option is $I, II, III$.

Which of the following reactants can be reduced by $SO_2$?
$I$. $O_3 \to$ product
$II$. $Cr_2O_7^{2-} \xrightarrow{H^{+}} $ product
$III$. $MnO_4^- \xrightarrow{H^{+}} $ product
$IV$. $H_2S \longrightarrow $ product

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Which of the following reactants can be reduced by $SO_2$?$I$. $O_3 \to$ product$II$. $Cr_2O_7^{2-} \xrightarrow{H^{+}} $ product$III$. $MnO_4^- \xrightarrow{H^{+}} $ product$IV$. $H_2S \longrightarrow $ product