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(D) The reaction of an alkyl halide with alcoholic $KCN$ is a nucleophilic substitution reaction ($S_N2$ mechanism) that produces an alkyl cyanide (ni

Vedclass · Accepted Answer

$n-$Propylchloride and alcoholic $KCN$

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(D) The reaction of an alkyl halide with alcoholic $KCN$ is a nucleophilic substitution reaction ($S_N2$ mechanism) that produces an alkyl cyanide (nitrile).To obtain butanenitrile $(CH_3CH_2CH_2CH_2CN)$,which contains $4$ carbon atoms in the chain plus the nitrile carbon,we need a starting alkyl halide with $4$ carbon atoms.$n-$Propylchloride $(CH_3CH_2CH_2Cl)$ has $3$ carbons,so it would yield butanenitrile $(CH_3CH_2CH_2CN)$ which is $3$ carbons in the chain plus the nitrile carbon,totaling $4$ carbons.Wait,butanenitrile is $CH_3CH_2CH_2CN$. This contains $4$ carbon atoms in total.Therefore,$n-$propylchloride $(CH_3CH_2CH_2Cl)$ reacts with $KCN$ to form $CH_3CH_2CH_2CN$ (butanenitrile).Reaction: $CH_3CH_2CH_2Cl + KCN 	ext{ (alc.)} ightarrow CH_3CH_2CH_2CN + KCl$.

Which of the following pairs of compounds on heating gives butanenitrile?

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