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(D) To calculate the percentage of carbon,use the formula: $	ext{Percentage of C} = \frac{	ext{Total mass of C}}{	ext{Molar mass of compound}} 	im

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$CH_3COOH$ and $C_6H_{12}O_6$

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(D) To calculate the percentage of carbon,use the formula: $	ext{Percentage of C} = \frac{	ext{Total mass of C}}{	ext{Molar mass of compound}} 	imes 100$. For $CH_3COOH$ $(C_2H_4O_2)$: Molar mass = $2(12) + 4(1) + 2(16) = 60 \ g/mol$. Percentage of $C$ = $\frac{24}{60} 	imes 100 = 40\%$. For $C_6H_{12}O_6$: Molar mass = $6(12) + 12(1) + 6(16) = 180 \ g/mol$. Percentage of $C$ = $\frac{72}{180} 	imes 100 = 40\%$. Since both compounds have $40\%$ carbon,the correct pair is $CH_3COOH$ and $C_6H_{12}O_6$.

Which of the following pairs of species has the same percentage of carbon?

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