Which of the following orders of atomic radiu | vedclass

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(A) The atomic radius increases down a group due to the addition of new shells. However,for $4d$ and $5d$ transition series elements,the atomic radii

Vedclass · Accepted Answer

$Sc < Y \approx La$

Vedclass · Answer

(A) The atomic radius increases down a group due to the addition of new shells. However,for $4d$ and $5d$ transition series elements,the atomic radii are very similar due to the lanthanoid contraction. $1$. For $Sc$,$Y$,and $La$ (Group $3$): $Sc $2$. For $K$,$Rb$,and $Cs$ (Group $1$): The radius increases as $K $3$. For $Ge$,$Sn$,and $Pb$ (Group $14$): The radius increases as $Ge $4$. For $Ni$,$Pd$,and $Pt$ (Group $10$): $Ni Since both $A$ and $D$ represent correct trends,$A$ is the most standard representation for the group $3$ elements.

$Column\, A$ (ion)	$Column\, B$ (radius)
$(i)$ $Li^{+}$	$(p)$ $216\, pm$
$(ii)$ $Na^{+}$	$(q)$ $195\, pm$
$(iii)$ $Br^{-}$	$(r)$ $60\, pm$
$(iv)$ $I^{-}$	$(s)$ $95\, pm$

Which of the following orders of atomic radius is correct?

Similar Questions

The correct order of atomic radii of given elements is

$Na^{+}$,$Mg^{2+}$,$Al^{3+}$,and $Si^{4+}$ are isoelectronic. Their ionic size follows the order:

The smallest cation and the smallest anion are respectively

Match $Column\, A$ with $Column\, B$:
$Column\, A$ (ion) $Column\, B$ (radius)
$(i)$ $Li^{+}$ $(p)$ $216\, pm$
$(ii)$ $Na^{+}$ $(q)$ $195\, pm$
$(iii)$ $Br^{-}$ $(r)$ $60\, pm$
$(iv)$ $I^{-}$ $(s)$ $95\, pm$

Which of the following is arranged in order of increasing radius?

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