Which of the following molecules contains 25 | vedclass

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(C) The percentage of $s$-character in a hybrid orbital is calculated as: $s$-character $= (\frac{1}{n}) 	imes 100$,where $n$ is the number of hybrid

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Methane

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(C) The percentage of $s$-character in a hybrid orbital is calculated as: $s$-character $= (\frac{1}{n}) 	imes 100$,where $n$ is the number of hybrid orbitals. For $sp^{3}$ hybridization,there are $4$ hybrid orbitals,so $s$-character $= (\frac{1}{4}) 	imes 100 = 25 \%$. In $CH_{4}$ (Methane),the carbon atom is $sp^{3}$-hybridized. In $C_{2}H_{4}$ (Ethylene),carbon is $sp^{2}$-hybridized ($33.3 \% \,s$-character). In $C_{2}H_{2}$ (Acetylene),carbon is $sp$-hybridized ($50 \% \,s$-character). In $C_{6}H_{6}$ (Benzene),carbon is $sp^{2}$-hybridized ($33.3 \% \,s$-character). Therefore,methane contains $25 \% \,s$-character.

Which of the following molecules contains $25 \% \,s$-character of the carbon atom in its hybrid state?

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