Which of the following molecules/species is t | vedclass

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Question

(A) To determine the stability of the given species,we apply $H$ückel's rule for aromaticity:$1$. $A$: The cyclopropenyl cation has $2 \pi$ electrons

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Cyclopropenyl cation

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(A) To determine the stability of the given species,we apply $H$ückel's rule for aromaticity:$1$. $A$: The cyclopropenyl cation has $2 \pi$ electrons ($n=0$,$4n+2=2$),is planar,and cyclic. It is aromatic and highly stable.$2$. $B$: The cyclopentadienyl cation has $4 \pi$ electrons $(4n=4)$,which makes it anti-aromatic and unstable.$3$. $C$: The cyclopropenyl anion has $4 \pi$ electrons $(4n=4)$,which makes it anti-aromatic and unstable.$4$. $D$: $1,3$-Cyclohexadiene is a non-aromatic conjugated diene,which is less stable than an aromatic system.Therefore,the cyclopropenyl cation is the most stable species due to its aromatic character.

Column $-I$	Column $-II$
$A$. Free radical	$1$. Trigonal planar
$B$. Carbocation	$2$. Pyramidal
$C$. Carbanion	$3$. Linear

Which of the following molecules/species is the most stable?

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Column $-I$ Column $-II$

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