Which of the following molecules possesses a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To determine the hybridization of carbon atoms in the given molecules,we look at the structure of $CH_2=CH-C\equiv CH$ (Butenyne).In Butenyne,the

Vedclass · Accepted Answer

Butenyne

Vedclass · Answer

(A) To determine the hybridization of carbon atoms in the given molecules,we look at the structure of $CH_2=CH-C\equiv CH$ (Butenyne).In Butenyne,the structure is $CH_2=CH-C\equiv CH$.The carbon atoms are numbered as $C_1=C_2-C_3\equiv C_4$.$C_1$ is $sp^2$ hybridized,$C_2$ is $sp^2$ hybridized,$C_3$ is $sp$ hybridized,and $C_4$ is $sp$ hybridized.The bond between $C_2$ and $C_3$ is formed by the overlap of an $sp^2$ orbital from $C_2$ and an $sp$ orbital from $C_3$.Therefore,Butenyne contains an $sp^2-sp$ sigma bond.

Which of the following molecules possesses a bond formed by $sp^2-sp$ orbital overlap?

Similar Questions

Explain the characteristics of $\pi$ bonds. Or,give the requirements for the formation of $\pi$ bonds and explain the active centers.

Considering the $x$-axis as the internuclear axis,which of the following will not form a sigma $(\sigma)$ bond and why?
$(a)$ $1s$ and $1s$
$(b)$ $1s$ and $2p_{x}$
$(c)$ $2p_{y}$ and $2p_{y}$
$(d)$ $1s$ and $2s$

What type of bond is formed by the overlapping of $2p_x$ and $2p_y$ orbitals? Why?

If the internuclear axis is the $z$-axis,then in which of the following cases are $\sigma$ and $\pi$ bonds not possible?

Distinguish between a sigma and a pi bond.

Vedclass Test Series

Exam Paper Generator

Online Exam Module