(B) In $NH_3$,the central nitrogen atom has $5$ valence electrons. It forms $3$ covalent bonds with $3$ hydrogen atoms,leaving one lone pair (non-bond

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(B) In $NH_3$,the central nitrogen atom has $5$ valence electrons. It forms $3$ covalent bonds with $3$ hydrogen atoms,leaving one lone pair (non-bonding electrons) on the nitrogen atom. $CH_4$ has $0$ lone pairs,$H_2O$ has $2$ lone pairs,and $HF$ has $3$ lone pairs. Therefore,the correct option is $(B)$.